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#21
Stunts Chat / Re: Stunts elements in real li...
Last post by Daniel3D - April 17, 2024, 01:49:41 PMQuote from: Duplode on April 17, 2024, 12:45:45 PMIt would be higher than that for 6g -- 89.8 mph -- because centripetal acceleration grows with the square of the speed.That could be an Ultimate Gentlemen Agreement Rule. UGAR.
The looping may not be taken with a speed exceeding 100 mph.
#22
Stunts Chat / Re: Stunts elements in real li...
Last post by Duplode - April 17, 2024, 12:45:45 PMIt would be higher than that for 6g -- 89.8 mph -- because centripetal acceleration grows with the square of the speed.
#23
Stunts Modification Projects / Re: Color changing of the need...
Last post by Spoonboy - April 17, 2024, 11:17:39 AMSeeing this thread appear reminded me of an issue I saw. @Ryoma, would it be possible to change the needle colour in the Koenig Testarossa??
I'd love to test this car more, but the white needles on white dials make this difficult. Don't want to give you another job, but just thought I'd ask
I'd love to test this car more, but the white needles on white dials make this difficult. Don't want to give you another job, but just thought I'd ask
#24
Stunts Chat / Re: Stunts elements in real li...
Last post by Daniel3D - April 17, 2024, 09:06:52 AMSo, to get around the more comfortable 6g you would only need ~32 mph to go around the loop i guess.
#25
Stunts Chat / Re: Stunts elements in real li...
Last post by Cas - April 17, 2024, 02:30:25 AMAbsolutely inhuman, ha, ha. Well, I hit some numbers wrong, but I assure you that you need a very large loop still for that speed. If it were possible to build a stable loop big enough, it would be a lot easier to do the stunt.
#26
Stunts Chat / Re: Stunts elements in real li...
Last post by Duplode - April 16, 2024, 11:58:38 PMWe gotta divide rather than multiply by 3.6 when converting to m/s. That gives a speed of 109.5 m/s and thus, by the formula above, a (still quite scary!) acceleration in g of 1223m / r.
What is the radius of a Stunts loop, though? Let's stick with the basic conversion factor for the in-game physics: 1 track tile = 1024 3SH units = 205 feet. Like most roller coaster loops, the Stunts loop isn't perfectly circular; however, the upper half is close enough for using the extreme z coordinates (that is, along the direction of the track) for the radius:
That means a radius of 449 3SH units, or 89.89 ft, or 27.40 m. The acceleration, therefore, would be an extreme 44.64 g!
What is the radius of a Stunts loop, though? Let's stick with the basic conversion factor for the in-game physics: 1 track tile = 1024 3SH units = 205 feet. Like most roller coaster loops, the Stunts loop isn't perfectly circular; however, the upper half is close enough for using the extreme z coordinates (that is, along the direction of the track) for the radius:
That means a radius of 449 3SH units, or 89.89 ft, or 27.40 m. The acceleration, therefore, would be an extreme 44.64 g!
#27
Chat - Misc / Re: Association game
Last post by Shoegazing Leo - April 16, 2024, 11:17:16 PM #28
Chat - Misc / Re: Association game
Last post by Cas - April 16, 2024, 10:31:27 PM(Note on the last one for non-Spanish speakers: Pope and potato are translated the same into Spanish 
)
Mash
)Mash
#29
Stunts Modification Projects / Re: Color changing of the need...
Last post by Cas - April 16, 2024, 10:30:41 PMThanks, Zapper! Yes, I was sure I had skipped it! It had to be there. I've already obtained it from the CCC Stunts download, but I knew it had to be in the forum. Cheers!
#30
Stunts Chat / Re: Stunts elements in real li...
Last post by Cas - April 16, 2024, 10:29:14 PMWow! Amazing! 
Well, acceleration is v squared by radius, so for 245 mph, which are 394 km/h, that is, 1418.4 m/s, we have a = (1418.4 m/s)^2 / r. If we want g force, we need to divide that by gravity acceleration on the surface of Earth, roughly 9.81 m/s^2, so:
g = (2011858.56 m^2/s^2) / (r * 9.81 m/s^2) = 205082.422 m / r
It still depends on the radius. If you don't want to die, but want to make sure you'll get some grip at the top (since actual tangential speed won't be constant), a maximum of some 6g, like in the video, sounds like a safe bet. To make that g value, you'd need a loop to be some 34 km in radius, ha, ha... That square in V really makes a difference!
With a loop that big, the good thing is that it'd be much easier to drive through it and speed would be a lot more constant than in the video, so g force would also be more stable. Then you can afford a bigger loop to have a lower max g as well. The problem is how you will build such a huge loop strong enough to withstand itself and the car.
Duplode, you're better a math guy than I... Let me know if I'm doing my calculations correctly, ha, ha
Well, acceleration is v squared by radius, so for 245 mph, which are 394 km/h, that is, 1418.4 m/s, we have a = (1418.4 m/s)^2 / r. If we want g force, we need to divide that by gravity acceleration on the surface of Earth, roughly 9.81 m/s^2, so:
g = (2011858.56 m^2/s^2) / (r * 9.81 m/s^2) = 205082.422 m / r
It still depends on the radius. If you don't want to die, but want to make sure you'll get some grip at the top (since actual tangential speed won't be constant), a maximum of some 6g, like in the video, sounds like a safe bet. To make that g value, you'd need a loop to be some 34 km in radius, ha, ha... That square in V really makes a difference!
With a loop that big, the good thing is that it'd be much easier to drive through it and speed would be a lot more constant than in the video, so g force would also be more stable. Then you can afford a bigger loop to have a lower max g as well. The problem is how you will build such a huge loop strong enough to withstand itself and the car.
Duplode, you're better a math guy than I... Let me know if I'm doing my calculations correctly, ha, ha